GUESS
PAPER SUMMATIVE ASSESSMENT –I (2012) Class
– IX (Chemistry
|
Section
A
|
1.What is
dry ice ? What happens when the pressure under which it is stored is
decreased to
|
1 atmosphere ?
|
2.Why is glass or chinaware packed with straw ?
|
3.Name the processes by which CO2 and H2O
move into and out of the cell ?
|
4.List in tabular form any two differences between
homogeneous and heterogeneous mixtures.
|
5. (a) Define evaporation. (b)
Explain how the following factors affect the rate of evaporation of a liquid:
|
(i) temperature of the liquid. (ii) area of the
exposed surface.
|
(iii) moisture in the surrounding air. (iv) Increase in wind speed.
|
6.(i) Name the process or the separation technique
you would follow to separate : (a) Dyes in black ink (b) Butter from cream
(c) Ammonium chloride and common salt (d) Iron filings and sand (ii) State
the principle used in separation by centrifugation.
|
7. Based on the following characteristics
distinguish in tabular form the behavior of true solution, suspension and
colloidal solution. (a) appearance (b) visibility (c) filterability (d)
Tyndall effect (e) particle size OR
|
(a) What is distillation ? List the two conditions
essential for using this as a method of separation of components of a
mixture. (b) Draw a labelled diagram of the apparatus used to separate a
mixture of two miscible liquids.
|
8..Compare in tabular form , the properties of
Solids, Liquids and Gases with respect to : (i) Shape (ii) Volume (iii)
Compressibility (iv) Diffusion (v) Fluidity or Rigidity
|
OR ,
|
Account for the following : (a) For any physical
state of a substance, the temperature remains constant during its change of
state. (b) Water kept in an earthen pot becomes cool in summer. (c) We are
able to sip hot tea from a saucer rather than from a cup.
|
Section
B
|
09.If common salt is added to the unsaturated
solution of water and common salt it will
|
(a) become a colloid (b) become a suspension (c)
start showing Tyndall effect (d) remain a true solution
|
10.A student was asked to mix the white of an egg
with water and stir well. The student observed that
|
(a) a transparent solution is formed. (b) a translucent mixture is formed.
|
(c) egg white settles down at the bottom. (d) egg white floats on the surface.
|
11.The reaction of iron and sulphur to form iron
sulphide takes place at :
|
(a) at high temperature (b) in the
presence of a catalyst
|
(c) at
moderate temperature (d) in the presence
of an acid
|
12.Which of the following compounds when dissolved
in water gives coloured solution ?
|
(a) barium chloride (b) sugar solution (c) sodium
chloride (d) copper sulphate
|
13.For determining the accurate melting point of
ice we should prefer
|
(a) ice made from distilled water (b) ice made from tap water
|
(c) crushed dry ice mixed with salt (d) a mixture of ice and salt
|
14.Mohan used a thermometer having 20 divisions
between 30degC mark and 40degC mark. While determining
boiling point of water using this thermometer he observed that the level of
mercury becomes constant just 3 division below the 100o C mark.
Mohan should record in his note book
|
(a)
Least count=0.5degC, B.P.=97degC (b) L.C.=0.5degC, B.P.=98.5degC
|
(c)
L.C.=1degC, B.P.=98.5degC (d) L.C.=1degC ,
B.P.=97degC
|
15.Ramu
was asked to separate a mixture of common salt and ammonium chloride.
Sublimation is used to separate ammonium chloride because :
|
(a)
ammonium chloride sublimes
|
(b)
ammonium chloride changes directly from solid to gaseous state on heating
|
(c)
mixture contain a sublimable volatile component and a non Sublimable impurity
(salt)
|
(d) all
the above
|
16.Which
is the correct colour sequence of iron filings, sulphur and iron sulphide ?
|
(a) Greyish
black, yellow, black (b)
Black, yellow, brown
|
(c)
Brown, yellow, black (d) Black , yellow,
greyish black
|
17.The
colour of magnesium after rubbing with sand paper is
|
(a)
Silvery white (b) Grey (c) Black (d) Brown
|
18.Common
salt and sand can be separated by :
|
(a)
Filtration (b) Crystallisation (c) Sedimentation and Decantation
|
(d)
First dissolving in water, then by filtration and followed by
crystallisation.
|
19.A
student put five raisins each in two beakers A and B. Beaker A contained 20
mL of distilled water and beaker B has 20 mL of saturated sugar solution.
After some time the student would observe that :
|
(a) raisins in beaker A were more swollen
than those in beaker B.
|
(b)
raisins in beaker B were more swollen than those in beaker A.
|
(c)
raisins in both beakers A and B were equally swollen.
|
(d)
raisins in beaker A did not swell up at all.
|
20.In
the preparation of temporary mount of onion peel which of the following is
not used :
|
(a)
water (b) glycerine (c) safranin (d) alcohol
|
21.Arun,
Deepa, Uma and Priya were asked to select a plant material which would not
give blue black colour with iodine solution. Who did not select the right
material ?
|
(a)
Arun selected maize grains. (b) Deepa selected wheat grains.
|
(c) Uma
selected ground nut seeds. (d)
Priya selected potato.
|
22.Deepak
washed a few grains of tur dal in water. The water became yellow. He then
added a few drops of HCl to the same test tube, the water turned pink
in colour. From the above test Deepak concluded that tur dal contains. (a)
proteins (b) starch (c) turmeric (d) metanil yellow HCl
|
23.A
student recorded the mass of dry raisins as 2.5g and the mass of raisins
after soaking in water as 4 g . While performing the above experiment. The
percentage of water absorbed by raisin is :
|
(a) 20%
(b) 30% (c) 60% (d) 40%
|
24.The mixture of sand and water when filtered
gives.
|
(a) pale brown solution (b) brown
solution
|
(c) transparent solution (d) grey
solution
|
25. When a mixture of sulphur powder and iron
filings is heated.
|
(a) iron filings starts melting (b) sulphur sublimates leaving iron
filling behind
|
(c) ferrous sulphide is formed. (d) sulphur melts
|
Thursday, September 20, 2012
GUESS PAPER SUMMATIVE ASSESSMENT –I (2011) SCIENCE- Class – IX (Chemistry)
Subscribe to:
Post Comments (Atom)
1 comment:
Q. Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of decent.
Answer: Time of ascent be t seconds and the object be thrown with an initial velocity be u m/s.
V2 – u2 = -2gh
02 - u2 = - 2gh
u2 = 2gh ----(i)
Also,
t1 = (v-u)/-g
t1 = (0-u)/-g
t1 = u/g --------------(ii)
Descent:
Time of descent be t ' seconds and the object final velocity be v m/s. The distance covered will be the same as when the object is thrown upwards.
V2 – u2 = -2gh
v2 - 02 = - 2gh
v2 = 2gh ----(iii)
Also,
t2 = (v-0)/g
t2 = (v -0)/g
t2 = v/g --------------(iv)
From equation (i) and (iii) we can see that u = v. -----(v)
Also, From equation (ii) ,(iv) and (v) we can see that
t1 = t2 , that is, time of ascent is equal to time of descent.
Post a Comment